MINI LESSON
Solving Linear Equations
To solve a linear equation, isolate the variable by undoing operations while keeping the equation balanced.
When fractions are present, multiplying both sides by a common denominator can simplify the work.
When variables appear with parameters like \(a\), solve the same way by factoring the variable when needed.
Always check which answer choice matches the simplified result.
Question 1
The solution to \(\frac{4(x-5)}{3}+2=14\) is
Question 2
The solution to the equation \(\frac{2(3x-1)}{3}=x+2\) is
Question 3
When solving \(-2(3x-5)=\frac{9}{2}x-2\) for \(x\), the solution is
Question 4
When solved for \(x\) in terms of \(a\), the solution to the equation \(3x-7=ax+5\) is
Question 5
When the equation \(6-ax=ax-2\) is solved for \(x\) in terms of \(a\), and \(a\neq0\), the result is